Lanthanum Ionization Energy

The Lanthanum Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Lanthanum.
La -> La⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Lanthanum is:
La^N+ -> La^(N+1)+ + e^-

La -> La¹⁺ = 538.1 kJ/mol = 128.73 Kcal/mol
La¹⁺ -> La²⁺ = 1067 kJ/mol = 255.26 Kcal/mol
La²⁺ -> La³⁺ = 1850 kJ/mol = 442.58 Kcal/mol
La³⁺ -> La⁴⁺ = 4819 kJ/mol = 1152.87 Kcal/mol
La⁴⁺ -> La⁵⁺ = 6400 kJ/mol = 1531.10 Kcal/mol
La⁵⁺ -> La⁶⁺ = 7600 kJ/mol = 1818.18 Kcal/mol
La⁶⁺ -> La⁷⁺ = 9600 kJ/mol = 2296.65 Kcal/mol
La⁷⁺ -> La⁸⁺ = 11000 kJ/mol = 2631.58 Kcal/mol
La⁸⁺ -> La⁹⁺ = 12400 kJ/mol = 2966.51 Kcal/mol
La⁹⁺ -> La¹⁰⁺ = 15900 kJ/mol = 3803.83 Kcal/mol